What is the answer to (x-4)(x-3)=x^2+2x+8 ?

The answer to (x-4)(x-3)=x^2+2x+8 is x= 4/9

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(x-4)(x-3)=x^2+2x+8

(x - 4) (x - 3) = x^{2} + 2 x + 8

x = \frac{4}{9}

Decimal Notation

x = 0.44444 \dots

Solution steps

(x - 4) (x - 3) = x^{2} + 2 x + 8

Expand

(x - 4) (x - 3) : x^{2} - 7 x + 12

x^{2} - 7 x + 12 = x^{2} + 2 x + 8

Move

12

to the right side

x^{2} - 7 x = x^{2} + 2 x - 4

Subtract

x^{2} + 2 x

from both sides

x^{2} - 7 x - (x^{2} + 2 x) = x^{2} + 2 x - 4 - (x^{2} + 2 x)

Simplify

- 9 x = - 4

Divide both sides by

- 9

x = \frac{4}{9}

1 - 2 x = 4 x

- 1.8 r - 19.6 = - 6.7 r + 19.6

4 x = 120

\frac{x}{- 3} = 12

5 x + 10 = 40

What is the answer to (x-4)(x-3)=x^2+2x+8 ?
The answer to (x-4)(x-3)=x^2+2x+8 is x= 4/9
Solve for x: (x-4)(x-3)=x^2+2x+8
The solution is x= 4/9