What is the answer to 3(x+5)-7(1-x)=8(x-4)-2(x+1) ?

The answer to 3(x+5)-7(1-x)=8(x-4)-2(x+1) is x=-21/2

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3(x+5)-7(1-x)=8(x-4)-2(x+1)

3 (x + 5) - 7 (1 - x) = 8 (x - 4) - 2 (x + 1)

x = - \frac{21}{2}

Solution steps

3 (x + 5) - 7 (1 - x) = 8 (x - 4) - 2 (x + 1)

Expand

3 (x + 5) - 7 (1 - x) : 10 x + 8

Expand

8 (x - 4) - 2 (x + 1) : 6 x - 34

10 x + 8 = 6 x - 34

Move

8

to the right side

10 x = 6 x - 42

Move

6 x

to the left side

4 x = - 42

Divide both sides by

4

x = - \frac{21}{2}

\frac{x + 1}{4} + \frac{x - 1}{2} = 2

2 x + 3 = 8 - 3 x

f = lo g_{10} (1)

- 4 z = 1

- 5 (2 - x) = 20

What is the answer to 3(x+5)-7(1-x)=8(x-4)-2(x+1) ?
The answer to 3(x+5)-7(1-x)=8(x-4)-2(x+1) is x=-21/2
Solve for x: 3(x+5)-7(1-x)=8(x-4)-2(x+1)
The solution is x=-21/2