What are the solutions to the equation 3y^2=12 ?

The solutions to the equation 3y^2=12 are y=2,y=-2

Find the zeros of 3y^2=12

The zeros of 3y^2=12 are y=2,y=-2

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3 y^{2} = 12

y = 2, y = - 2

Solution steps

3 y^{2} = 12

Divide both sides by

3

y^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 4, y = - 4

4 = 2

- 4 = - 2

y = 2, y = - 2

121 x^{2} - 9 y^{4}

(- 2)^{6}

a^{2} - 11 a - 12

∣ x - 2 ∣ = - 10

3 x^{2} - 2 x + 4 = 0

What are the solutions to the equation 3y^2=12 ?
The solutions to the equation 3y^2=12 are y=2,y=-2
Find the zeros of 3y^2=12
The zeros of 3y^2=12 are y=2,y=-2