What is the answer to ((2x-1))/3-((3x-2))/4 =-11/12 ?

The answer to ((2x-1))/3-((3x-2))/4 =-11/12 is x=13

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((2x-1))/3-((3x-2))/4 =-11/12

\frac{( 2 x - 1 )}{3} - \frac{( 3 x - 2 )}{4} = - \frac{11}{12}

x = 13

Solution steps

\frac{( 2 x - 1 )}{3} - \frac{( 3 x - 2 )}{4} = - \frac{11}{12}

\frac{2 x - 1}{3} - \frac{3 x - 2}{4} = - \frac{11}{12}

Multiply by LCM

4 (2 x - 1) - 3 (3 x - 2) = - 11

Expand

4 (2 x - 1) - 3 (3 x - 2) : - x + 2

- x + 2 = - 11

Move

2

to the right side

- x = - 13

Divide both sides by

- 1

x = 13

\frac{4 a - 2}{3} = \frac{5 ( a + 3 )}{2}

x, y - 3 = \frac{1}{3} (x - (- 4))

- 3 x - 2 + 16 (2 x + 1) = - \frac{2 ( 6 x - 4 )}{8}

b = 2 - \frac{2 b - 4}{3}

x, z = 3 x - 2 x y

What is the answer to ((2x-1))/3-((3x-2))/4 =-11/12 ?
The answer to ((2x-1))/3-((3x-2))/4 =-11/12 is x=13
Solve for x: ((2x-1))/3-((3x-2))/4 =-11/12
The solution is x=13