What is the answer to a(x/(bc)-1)=1 ?

The answer to a(x/(bc)-1)=1 is x=(bc)/a+bc;\quad a\ne 0,bc\ne 0

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a(x/(bc)-1)=1

a (\frac{x}{b c} - 1) = 1

x = \frac{b c}{a} + b c; a \neq = 0, b c \neq = 0

Solution steps

a (\frac{x}{b c} - 1) = 1

Divide both sides by

a; a \neq = 0

\frac{x}{b c} - 1 = \frac{1}{a}; a \neq = 0

Move

1

to the right side

\frac{x}{b c} = \frac{1}{a} + 1; a \neq = 0

Multiply both sides by

b c

x = \frac{b c}{a} + b c; a \neq = 0, b c \neq = 0

3 (x + 8) = 6 (x - 2) + 24

5 x + 1 = 2 x + 1

2 (l - 1) - 3 (l - 4) = 4 l

4 x + 2 = - 9 + 7 x

8^{2} = 135

What is the answer to a(x/(bc)-1)=1 ?
The answer to a(x/(bc)-1)=1 is x=(bc)/a+bc;\quad a\ne 0,bc\ne 0