What is the answer to solvefor a,(3a-2)+(b-2)=12 ?

The answer to solvefor a,(3a-2)+(b-2)=12 is a=(-b+16)/3

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solvefor a,(3a-2)+(b-2)=12

solve for

a, (3 a - 2) + (b - 2) = 12

a = \frac{- b + 16}{3}

Solution steps

(3 a - 2) + (b - 2) = 12

Remove parentheses:

(a) = a

3 a - 2 + b - 2 = 12

Group like terms

3 a + b - 2 - 2 = 12

Subtract the numbers:

- 2 - 2 = - 4

3 a + b - 4 = 12

Move

b

to the right side

3 a - 4 = 12 - b

Move

4

to the right side

3 a = - b + 16

Divide both sides by

3

a = \frac{- b + 16}{3}

x, 3 y + 4 x = 0

\frac{3}{2} - \frac{8}{3} x = 11

8 x - 5 = 19

69 x + 58 = 90 - 187 x

- (- 2 t - 9) = - 2 t + 3

What is the answer to solvefor a,(3a-2)+(b-2)=12 ?
The answer to solvefor a,(3a-2)+(b-2)=12 is a=(-b+16)/3