What are the solutions to the equation 3x^2+9x=-4 ?

The solutions to the equation 3x^2+9x=-4 are x=(-9+sqrt(33))/6 ,x=(-9-sqrt(33))/6

Find the zeros of 3x^2+9x=-4

The zeros of 3x^2+9x=-4 are x=(-9+sqrt(33))/6 ,x=(-9-sqrt(33))/6

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3 x^{2} + 9 x = - 4

x = \frac{- 9 + 33}{6}, x = \frac{- 9 - 33}{6}

Decimal Notation

x = - 0.54257 \dots, x = - 2.45742 \dots

Solution steps

3 x^{2} + 9 x = - 4

Move

4

to the left side

3 x^{2} + 9 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

9^{2} - 4 \cdot 3 \cdot 4 = 33

x_{1, 2} = \frac{- 9 \pm 33}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 9 + 33}{2 \cdot 3}, x_{2} = \frac{- 9 - 33}{2 \cdot 3}

x = \frac{- 9 + 33}{2 \cdot 3} : \frac{- 9 + 33}{6}

x = \frac{- 9 - 33}{2 \cdot 3} : \frac{- 9 - 33}{6}

The solutions to the quadratic equation are:

x = \frac{- 9 + 33}{6}, x = \frac{- 9 - 33}{6}

5 x - 8 \geq 12

x - 3 < 1

6 x^{2} - 12 x - 1 > 0

x^{2} > - 5 x + 36

- \frac{15}{5}

What are the solutions to the equation 3x^2+9x=-4 ?
The solutions to the equation 3x^2+9x=-4 are x=(-9+sqrt(33))/6 ,x=(-9-sqrt(33))/6
Find the zeros of 3x^2+9x=-4
The zeros of 3x^2+9x=-4 are x=(-9+sqrt(33))/6 ,x=(-9-sqrt(33))/6