What is the answer to (3x+2)/6+(2x-3)/2 =(x+5)/5 ?

The answer to (3x+2)/6+(2x-3)/2 =(x+5)/5 is x= 5/3

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(3x+2)/6+(2x-3)/2 =(x+5)/5

\frac{3 x + 2}{6} + \frac{2 x - 3}{2} = \frac{x + 5}{5}

x = \frac{5}{3}

Solution steps

\frac{3 x + 2}{6} + \frac{2 x - 3}{2} = \frac{x + 5}{5}

Multiply by LCM

5 (3 x + 2) + 15 (2 x - 3) = 6 (x + 5)

Expand

5 (3 x + 2) + 15 (2 x - 3) : 45 x - 35

Expand

6 (x + 5) : 6 x + 30

45 x - 35 = 6 x + 30

Move

35

to the right side

45 x = 6 x + 65

Move

6 x

to the left side

39 x = 65

Divide both sides by

39

x = \frac{5}{3}

A, 4 A + \frac{A}{3} = 400

2 + 2 (8347 - 4783) = - 2 j

- 2 x + (12 - 9) = 2 + 9 + 2 x

f = \frac{π}{10 \cdot 2}

X, 3 X + 2 Y = 7

What is the answer to (3x+2)/6+(2x-3)/2 =(x+5)/5 ?
The answer to (3x+2)/6+(2x-3)/2 =(x+5)/5 is x= 5/3
Solve for x: (3x+2)/6+(2x-3)/2 =(x+5)/5
The solution is x= 5/3