What is the answer to (2x-3)/5-(x+1)/2+3/5 x=2(x-4) ?

The answer to (2x-3)/5-(x+1)/2+3/5 x=2(x-4) is x= 23/5

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(2x-3)/5-(x+1)/2+3/5 x=2(x-4)

\frac{2 x - 3}{5} - \frac{x + 1}{2} + \frac{3}{5} x = 2 (x - 4)

x = \frac{23}{5}

Decimal Notation

x = 4.6

Solution steps

\frac{2 x - 3}{5} - \frac{x + 1}{2} + \frac{3}{5} x = 2 (x - 4)

Multiply by LCM

2 (2 x - 3) - 5 (x + 1) + 6 x = 20 (x - 4)

Expand

2 (2 x - 3) - 5 (x + 1) + 6 x : 5 x - 11

Expand

20 (x - 4) : 20 x - 80

5 x - 11 = 20 x - 80

Move

11

to the right side

5 x = 20 x - 69

Move

20 x

to the left side

- 15 x = - 69

Divide both sides by

- 15

x = \frac{23}{5}

\frac{2}{3} x - 4 = 20

\frac{5 - 3 x}{4} - \frac{x - 1}{3} = - 3 + \frac{x}{6}

0.7 x - 0.2 = 8.3 x + 7.2

a, a + b + c = 5

x, 18 x + 5 y = - 11

What is the answer to (2x-3)/5-(x+1)/2+3/5 x=2(x-4) ?
The answer to (2x-3)/5-(x+1)/2+3/5 x=2(x-4) is x= 23/5
Solve for x: (2x-3)/5-(x+1)/2+3/5 x=2(x-4)
The solution is x= 23/5