What are the solutions to the equation 10x^2+21x-10=0 ?

The solutions to the equation 10x^2+21x-10=0 are x= 2/5 ,x=-5/2

Find the zeros of 10x^2+21x-10=0

The zeros of 10x^2+21x-10=0 are x= 2/5 ,x=-5/2

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10 x^{2} + 21 x - 10 = 0

x = \frac{2}{5}, x = - \frac{5}{2}

Decimal Notation

x = 0.4, x = - 2.5

Solution steps

10 x^{2} + 21 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 10 ( - 10 )}{2 \cdot 10}

2 1^{2} - 4 \cdot 10 (- 10) = 29

x_{1, 2} = \frac{- 21 \pm 29}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 21 + 29}{2 \cdot 10}, x_{2} = \frac{- 21 - 29}{2 \cdot 10}

x = \frac{- 21 + 29}{2 \cdot 10} : \frac{2}{5}

x = \frac{- 21 - 29}{2 \cdot 10} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - \frac{5}{2}

(5 z + 1)^{2} + 100 = 0

- 3 (x - 1)^{2} - 6 = - 2 (x + 1)^{2} + 2

2 x = 3 x

x^{3} y^{2} + 8 x y^{2} + 5 x^{2} + 40

x (x + 2) = 3 (x + 2)

What are the solutions to the equation 10x^2+21x-10=0 ?
The solutions to the equation 10x^2+21x-10=0 are x= 2/5 ,x=-5/2
Find the zeros of 10x^2+21x-10=0
The zeros of 10x^2+21x-10=0 are x= 2/5 ,x=-5/2