What is the answer to M=log_{3}(12)+log_{3}(15)-log_{3}(20) ?

The answer to M=log_{3}(12)+log_{3}(15)-log_{3}(20) is M=2

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M=log_{3}(12)+log_{3}(15)-log_{3}(20)

M = lo g_{3} (12) + lo g_{3} (15) - lo g_{3} (20)

M = 2

Solution steps

M = lo g_{3} (12) + lo g_{3} (15) - lo g_{3} (20)

Simplify

lo g_{3} (12) + lo g_{3} (15) - lo g_{3} (20) : 2

M = 2

- x + 1 = 3

3 x + 4 (x - 8) = - 16 + 3 (x + 12)

x, x + y = 2 x

x, y - 2 x = - 3

6 a - 2 = 4 a + 12

What is the answer to M=log_{3}(12)+log_{3}(15)-log_{3}(20) ?
The answer to M=log_{3}(12)+log_{3}(15)-log_{3}(20) is M=2
Solve for M: M=log_{3}(12)+log_{3}(15)-log_{3}(20)
The solution is M=2