What is the answer to (2x-5)/3-(3x+1)/4 =(7-x)/2 ?

The answer to (2x-5)/3-(3x+1)/4 =(7-x)/2 is x=13

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(2x-5)/3-(3x+1)/4 =(7-x)/2

\frac{2 x - 5}{3} - \frac{3 x + 1}{4} = \frac{7 - x}{2}

x = 13

Solution steps

\frac{2 x - 5}{3} - \frac{3 x + 1}{4} = \frac{7 - x}{2}

Multiply by LCM

4 (2 x - 5) - 3 (3 x + 1) = 6 (- x + 7)

Expand

4 (2 x - 5) - 3 (3 x + 1) : - x - 23

Expand

6 (- x + 7) : - 6 x + 42

- x - 23 = - 6 x + 42

Move

23

to the right side

- x = - 6 x + 65

Move

6 x

to the left side

5 x = 65

Divide both sides by

5

x = 13

lo g_{10} (450) = x

x = \frac{0 + 0 \cdot 5 + 4}{2 \cdot 5 ^{2}}

x, y - y^{0} = m (x - x^{0})

x, 2 x + 2 y = 9

3 x - 1 = 2 x + 6

What is the answer to (2x-5)/3-(3x+1)/4 =(7-x)/2 ?
The answer to (2x-5)/3-(3x+1)/4 =(7-x)/2 is x=13
Solve for x: (2x-5)/3-(3x+1)/4 =(7-x)/2
The solution is x=13