What is the answer to x^2-1=(x-1)(x+1) ?

The answer to x^2-1=(x-1)(x+1) is True for all x

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x^2-1=(x-1)(x+1)

x^{2} - 1 = (x - 1) (x + 1)

True for all x

Solution steps

x^{2} - 1 = (x - 1) (x + 1)

Expand

(x - 1) (x + 1) : x^{2} - 1

x^{2} - 1 = x^{2} - 1

Move

1

to the right side

x^{2} = x^{2}

Move

x^{2}

to the left side

0 = 0

Both sides are equal

True for all x

x, 3 x - 4 y - 18 = 0

- x - 6 = 0

x - \frac{12 x + 1}{3} = 2 x + 1 - \frac{15 x + 4}{3}

x, x + y = 2 x - y - 2

0 = - x + 5

What is the answer to x^2-1=(x-1)(x+1) ?
The answer to x^2-1=(x-1)(x+1) is True for all x
Solve for x: x^2-1=(x-1)(x+1)
The solution is True for all x