What is the answer to d=sqrt((0-(-3))^2+(-2-(-3))^2) ?

The answer to d=sqrt((0-(-3))^2+(-2-(-3))^2) is d=sqrt(10)

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d=sqrt((0-(-3))^2+(-2-(-3))^2)

d = (0 - (- 3))^{2} + (- 2 - (- 3))^{2}

d = 10

Decimal Notation

d = 3.16227 \dots

Solution steps

d = (0 - (- 3))^{2} + (- 2 - (- 3))^{2}

Simplify

(0 - (- 3))^{2} + (- 2 - (- 3))^{2} : 10

d = 10

4 + \frac{x}{3} = x

\frac{x}{3} + 4 x = 39

2 (5) - 7 (3) = - 11

y = \frac{1}{1}

T, T (n) = \frac{3 n + 17}{n}

What is the answer to d=sqrt((0-(-3))^2+(-2-(-3))^2) ?
The answer to d=sqrt((0-(-3))^2+(-2-(-3))^2) is d=sqrt(10)
Solve for d: d=sqrt((0-(-3))^2+(-2-(-3))^2)
The solution is d=sqrt(10)