What is the answer to solvefor A,M=(BA)C ?

The answer to solvefor A,M=(BA)C is A= M/(BC);\quad C\ne 0,B\ne 0

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solvefor A,M=(BA)C

solve for

A, M = (B A) C

A = \frac{M}{BC}; C \neq = 0, B \neq = 0

Solution steps

M = (B A) C

Switch sides

B A C = M

Divide both sides by

C; C \neq = 0

A B = \frac{M}{C}; C \neq = 0

Divide both sides by

B; C \neq = 0, B \neq = 0

A = \frac{M}{BC}; C \neq = 0, B \neq = 0

\frac{3 x - 2}{4} - \frac{5 x - 1}{3} = \frac{2 x - 7}{6}

20 = \frac{3 + z}{5}

- \frac{4}{7} k = - 28

72 + x = 78.65

9 - 2 (3 x + 4) = 5 - 3 (x - 4)

What is the answer to solvefor A,M=(BA)C ?
The answer to solvefor A,M=(BA)C is A= M/(BC);\quad C\ne 0,B\ne 0