What is the answer to (x-1)/3-(x+2}{12}=\frac{x-2)/2 ?

The answer to (x-1)/3-(x+2}{12}=\frac{x-2)/2 is x=2

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(x-1)/3-(x+2}{12}=\frac{x-2)/2

\frac{x - 1}{3} - \frac{x + 2}{12} = \frac{x - 2}{2}

x = 2

Solution steps

\frac{x - 1}{3} - \frac{x + 2}{12} = \frac{x - 2}{2}

Multiply by LCM

4 (x - 1) - (x + 2) = 6 (x - 2)

Expand

4 (x - 1) - (x + 2) : 3 x - 6

Expand

6 (x - 2) : 6 x - 12

3 x - 6 = 6 x - 12

Move

6

to the right side

3 x = 6 x - 6

Move

6 x

to the left side

- 3 x = - 6

Divide both sides by

- 3

x = 2

y, 1 - y = x

3 t + \frac{1}{5} - 5 = \frac{1}{5} + 5 t

10 (5 x + 12) = 370

x, 20 x + 12 y = 72

z = - 6 + i^{135} + 8 i^{87} + - 121

What is the answer to (x-1)/3-(x+2}{12}=\frac{x-2)/2 ?
The answer to (x-1)/3-(x+2}{12}=\frac{x-2)/2 is x=2
Solve for x: (x-1)/3-(x+2}{12}=\frac{x-2)/2
The solution is x=2