What is the answer to solvefor a,d= 1/2 at^2 ?

The answer to solvefor a,d= 1/2 at^2 is a=(2d)/(t^2);\quad t\ne 0

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solvefor a,d= 1/2 at^2

solve for

a, d = \frac{1}{2} a t^{2}

a = \frac{2 d}{t ^{2}}; t \neq = 0

Solution steps

d = \frac{1}{2} a t^{2}

Switch sides

\frac{1}{2} a t^{2} = d

Multiply both sides by

2

a t^{2} = 2 d

Divide both sides by

t^{2}; t \neq = 0

a = \frac{2 d}{t ^{2}}; t \neq = 0

y = - 3^{2} - 4

\frac{m}{7} = \frac{9}{4}

- 5 x + 4 = - 4 x + 9

x, \frac{1}{3} (s - x) = xv + 3 a

\frac{4}{3} (x + 1) = 2 x - 1

What is the answer to solvefor a,d= 1/2 at^2 ?
The answer to solvefor a,d= 1/2 at^2 is a=(2d)/(t^2);\quad t\ne 0