What is the answer to solvefor j,j(-x)=(-x)^3+5 ?

The answer to solvefor j,j(-x)=(-x)^3+5 is j=-(-x^3+5)/x ;\quad x\ne 0

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solvefor j,j(-x)=(-x)^3+5

solve for

j, j (- x) = (- x)^{3} + 5

j = - \frac{- x ^{3} + 5}{x}; x \neq = 0

Solution steps

j (- x) = (- x)^{3} + 5

Simplify

(- x)^{3} + 5 : - x^{3} + 5

j (- x) = - x^{3} + 5

Divide both sides by

- x; x \neq = 0

j = - \frac{- x ^{3} + 5}{x}; x \neq = 0

x, \frac{2 x - y}{2 y} = 0.4

f = (1)^{2} - 2 (1) - 3

(0.25) (1) = x (0.0821) (27 + 273)

x, 3 x + y = 90

y, f = x^{3} + 2 x y - x + 2 y

What is the answer to solvefor j,j(-x)=(-x)^3+5 ?
The answer to solvefor j,j(-x)=(-x)^3+5 is j=-(-x^3+5)/x ;\quad x\ne 0