What is the answer to (2x+3)(3x-2)=6x^2+1 ?

The answer to (2x+3)(3x-2)=6x^2+1 is x= 7/5

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(2x+3)(3x-2)=6x^2+1

(2 x + 3) (3 x - 2) = 6 x^{2} + 1

x = \frac{7}{5}

Solution steps

(2 x + 3) (3 x - 2) = 6 x^{2} + 1

Expand

(2 x + 3) (3 x - 2) : 6 x^{2} + 5 x - 6

6 x^{2} + 5 x - 6 = 6 x^{2} + 1

Move

6

to the right side

6 x^{2} + 5 x = 6 x^{2} + 7

Move

6 x^{2}

to the left side

5 x = 7

Divide both sides by

5

x = \frac{7}{5}

12 = 15 (z - 51)

\frac{3}{4} \cdot X - (- \frac{2}{3}) = 1

4 x + 8 x + 12 x = 4 + 8 + 12

(2 x - 3) = 0

y - 2 = 1

What is the answer to (2x+3)(3x-2)=6x^2+1 ?
The answer to (2x+3)(3x-2)=6x^2+1 is x= 7/5
Solve for x: (2x+3)(3x-2)=6x^2+1
The solution is x= 7/5