What is the answer to solvefor a,z=(a-8)+(b-2)i ?

The answer to solvefor a,z=(a-8)+(b-2)i is a=(z+8)+i(2-b)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor a,z=(a-8)+(b-2)i

solve for

a, z = (a - 8) + (b - 2) i

a = (z + 8) + i (2 - b)

Solution steps

z = (a - 8) + (b - 2) i

Switch sides

a - 8 + (b - 2) i = z

a - 8 + i (b - 2) = z

Move

i (b - 2)

to the right side

a - 8 = z - i (b - 2)

Move

8

to the right side

a = z - i (b - 2) + 8

Simplify

a = (z + 8) + i (2 - b)

x, - 3 x + y = 18

2.7927 = (1 - x) \cdot 0.4231 + 8.4739 x

24 = a_{0} (0 + 3) (0 + 4)

\frac{- 3 x + 4}{2} = \frac{1}{3}

- 10 = - x + 3

What is the answer to solvefor a,z=(a-8)+(b-2)i ?
The answer to solvefor a,z=(a-8)+(b-2)i is a=(z+8)+i(2-b)