What are the solutions to the equation (10-1)(c^{12})=0 ?

The solutions to the equation (10-1)(c^{12})=0 are c=0

Find the zeros of (10-1)(c^{12})=0

The zeros of (10-1)(c^{12})=0 are c=0

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(10 - 1) (c^{12}) = 0

c = 0

Solution steps

(10 - 1) (c^{12}) = 0

Divide both sides by

9

c^{12} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

c = 0

The solution is

c = 0

h, c = \frac{a + b}{2} \cdot h

x - 3 = 2 x + 5

\frac{x}{3} + 5 = 11

2 x - 40 = x + 40

x, 8 x + 5 y = 1

What are the solutions to the equation (10-1)(c^{12})=0 ?
The solutions to the equation (10-1)(c^{12})=0 are c=0
Find the zeros of (10-1)(c^{12})=0
The zeros of (10-1)(c^{12})=0 are c=0