What is the answer to solvefor a, a/(11)+b/3 = 31/33 ?

The answer to solvefor a, a/(11)+b/3 = 31/33 is a=(31-11b)/3

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solvefor a, a/(11)+b/3 = 31/33

solve for

a, \frac{a}{11} + \frac{b}{3} = \frac{31}{33}

a = \frac{31 - 11 b}{3}

Solution steps

\frac{a}{11} + \frac{b}{3} = \frac{31}{33}

Move

\frac{b}{3}

to the right side

\frac{a}{11} = \frac{31}{33} - \frac{b}{3}

Multiply both sides by

11

a = \frac{31 - 11 b}{3}

(5 x - 3)^{2} - (4 x + 1)^{2} = (3 x + 2)^{2} - 4 (12 x + 5)

- (8 x - 9) - 3 = 5 + (- 5 x + 7)

3 (x + 2) = \frac{1}{4} (x - 3)

x - 1 = lo g_{8} (64)

3 x + 5 = 9 x - 4

What is the answer to solvefor a, a/(11)+b/3 = 31/33 ?
The answer to solvefor a, a/(11)+b/3 = 31/33 is a=(31-11b)/3