What is the answer to (2(x-1))/3+(3(2x+1))/9 =9 ?

The answer to (2(x-1))/3+(3(2x+1))/9 =9 is x=7

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(2(x-1))/3+(3(2x+1))/9 =9

\frac{2 ( x - 1 )}{3} + \frac{3 ( 2 x + 1 )}{9} = 9

x = 7

Solution steps

\frac{2 ( x - 1 )}{3} + \frac{3 ( 2 x + 1 )}{9} = 9

Cancel

\frac{3 ( 2 x + 1 )}{9} : \frac{2 x + 1}{3}

\frac{2 ( x - 1 )}{3} + \frac{2 x + 1}{3} = 9

Multiply both sides by

3

2 (x - 1) + 2 x + 1 = 27

Expand

2 (x - 1) + 2 x + 1 : 4 x - 1

4 x - 1 = 27

Move

1

to the right side

4 x = 28

Divide both sides by

4

x = 7

f = (\frac{4}{3})^{- 2}

6 (y - 2) = 3 (y + 2)

2 = - 5 + b

x, y - \frac{1}{2} x = - 5

\frac{x + 1}{3} - \frac{2 x - 1}{2} = 2 - \frac{5 x}{6}

What is the answer to (2(x-1))/3+(3(2x+1))/9 =9 ?
The answer to (2(x-1))/3+(3(2x+1))/9 =9 is x=7
Solve for x: (2(x-1))/3+(3(2x+1))/9 =9
The solution is x=7