What is 1/(3x-7)>= 4/(3-2x) ?

The solution to 1/(3x-7)>= 4/(3-2x) is 3/2 7/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1/(3x-7)>= 4/(3-2x)

\frac{1}{3 x - 7} \geq \frac{4}{3 - 2 x}

\frac{3}{2} < x \leq \frac{31}{14} or x > \frac{7}{3}

Interval Notation

(\frac{3}{2}, \frac{31}{14}] \cup (\frac{7}{3}, \infty)

Decimal Notation

1.5 < x \leq 2.21428 \dots or x > 2.33333 \dots

Solution steps

\frac{1}{3 x - 7} \geq \frac{4}{3 - 2 x}

Rewrite in standard form

\frac{- 14 x + 31}{( 3 x - 7 ) ( - 2 x + 3 )} \geq 0

Identify the intervals

\frac{3}{2} < x \leq \frac{31}{14} or x > \frac{7}{3}

x^{5} y^{3} - x^{2}

x^{3} > 4 x

4 x^{2} - 3 x - 4 = 0

3 x^{2} - 7 = - 19

\frac{x - 3}{x ^{2} + 9} \leq \frac{x}{x ^{2} + 3}

What is 1/(3x-7)>= 4/(3-2x) ?
The solution to 1/(3x-7)>= 4/(3-2x) is 3/2 <x<= 31/14 \lor x> 7/3