What is the answer to 2x(x+3y^2-sqrt(5))=2x^2+6xy^2-2xsqrt(5) ?

The answer to 2x(x+3y^2-sqrt(5))=2x^2+6xy^2-2xsqrt(5) is True for all x

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2x(x+3y^2-sqrt(5))=2x^2+6xy^2-2xsqrt(5)

2 x (x + 3 y^{2} - 5) = 2 x^{2} + 6 x y^{2} - 2 x 5

True for all x

Solution steps

2 x (x + 3 y^{2} - 5) = 2 x^{2} + 6 x y^{2} - 2 x 5

Expand

2 x (x + 3 y^{2} - 5) : 2 x^{2} + 6 x y^{2} - 25 x

2 x^{2} + 6 x y^{2} - 25 x = 2 x^{2} + 6 x y^{2} - 2 x 5

Subtract

2 x^{2} + 6 x y^{2} - 2 x 5

from both sides

2 x^{2} + 6 x y^{2} - 25 x - (2 x^{2} + 6 x y^{2} - 2 x 5) = 2 x^{2} + 6 x y^{2} - 2 x 5 - (2 x^{2} + 6 x y^{2} - 2 x 5)

Simplify

0 = 0

Both sides are equal

True for all x

x - \frac{x}{5} - \frac{x}{6} = 19

h, V = \frac{1}{3} A h

x, 12 x - 14 y = 20

1 + x = (\frac{62147100}{100000000})^{\frac{2}{5 + 1}}

12 - 2 (a + 3) = 8 + 3 (2 a + 5)

What is the answer to 2x(x+3y^2-sqrt(5))=2x^2+6xy^2-2xsqrt(5) ?
The answer to 2x(x+3y^2-sqrt(5))=2x^2+6xy^2-2xsqrt(5) is True for all x