What are the solutions to the equation 7x^2-6=-35 ?

The solutions to the equation 7x^2-6=-35 are x=sqrt(29/7)i,x=-sqrt(29/7)i

Find the zeros of 7x^2-6=-35

The zeros of 7x^2-6=-35 are x=sqrt(29/7)i,x=-sqrt(29/7)i

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7 x^{2} - 6 = - 35

x = \frac{29}{7} i, x = - \frac{29}{7} i

Solution steps

7 x^{2} - 6 = - 35

Move

6

to the right side

7 x^{2} = - 29

Divide both sides by

7

x^{2} = - \frac{29}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{29}{7}, x = - - \frac{29}{7}

- \frac{29}{7} = \frac{29}{7} i

- - \frac{29}{7} = - \frac{29}{7} i

x = \frac{29}{7} i, x = - \frac{29}{7} i

∣ 3 x - 6 ∣ \geq 4

2 m^{2} - 7 m - 660 = 0

6 x - 2 \leq 3 x - 6

4 (x + 2) = - 2 (x - 1)

\frac{x}{5} + 6.2 = - 6.3

What are the solutions to the equation 7x^2-6=-35 ?
The solutions to the equation 7x^2-6=-35 are x=sqrt(29/7)i,x=-sqrt(29/7)i
Find the zeros of 7x^2-6=-35
The zeros of 7x^2-6=-35 are x=sqrt(29/7)i,x=-sqrt(29/7)i