What is the answer to solvefor f,f(t+1/t)=t^2+1/(t^2) ?

The answer to solvefor f,f(t+1/t)=t^2+1/(t^2) is f=(t^4+1)/(t(t^2+1));\quad t\ne i,t\ne-i

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solvefor f,f(t+1/t)=t^2+1/(t^2)

solve for

f, f (t + \frac{1}{t}) = t^{2} + \frac{1}{t ^{2}}

f = \frac{t ^{4} + 1}{t ( t ^{2} + 1 )}; t \neq = i, t \neq = - i

Solution steps

f (t + \frac{1}{t}) = t^{2} + \frac{1}{t ^{2}}

Divide both sides by

t + \frac{1}{t}; t \neq = i, t \neq = - i

f = \frac{t ^{4} + 1}{t ( t ^{2} + 1 )}; t \neq = i, t \neq = - i

- 9 s + 42 = 2 s - 57

4 x - 9 = 2 x + 5

R = \frac{4}{3 + i} - \frac{2 - 3 i}{4} + \frac{7}{2 + i}

6 x - 3 (24 x - 5) = 2 (3 x - 1) - 8

\frac{( 1356 + 40 + 200 \cdot x + 35 )}{( 1560 + 40 + 200 )} = 0.9

What is the answer to solvefor f,f(t+1/t)=t^2+1/(t^2) ?
The answer to solvefor f,f(t+1/t)=t^2+1/(t^2) is f=(t^4+1)/(t(t^2+1));\quad t\ne i,t\ne-i