What is the answer to 14x-[2(3x-2)+8x]-[5x+2-(x-1)]=0 ?

The answer to 14x-[2(3x-2)+8x]-[5x+2-(x-1)]=0 is x= 1/4

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14x-[2(3x-2)+8x]-[5x+2-(x-1)]=0

14 x - [2 (3 x - 2) + 8 x] - [5 x + 2 - (x - 1)] = 0

x = \frac{1}{4}

Decimal Notation

x = 0.25

Solution steps

14 x - [2 (3 x - 2) + 8 x] - [5 x + 2 - (x - 1)] = 0

Expand

14 x - (2 (3 x - 2) + 8 x) - (5 x + 2 - (x - 1)) : - 4 x + 1

- 4 x + 1 = 0

Move

1

to the right side

- 4 x = - 1

Divide both sides by

- 4

x = \frac{1}{4}

x + 4 = - x + 8

3 x = 13

\frac{1}{3} x = 7

x, 8 x + 3 y - 5 = 0

4 x - 90 = 2 x - 38

What is the answer to 14x-[2(3x-2)+8x]-[5x+2-(x-1)]=0 ?
The answer to 14x-[2(3x-2)+8x]-[5x+2-(x-1)]=0 is x= 1/4
Solve for x: 14x-[2(3x-2)+8x]-[5x+2-(x-1)]=0
The solution is x= 1/4