What is the answer to solvefor f,f(sqrt(x-2))=2x^2-x+5 ?

The answer to solvefor f,f(sqrt(x-2))=2x^2-x+5 is f=(2x^2-x+5)/(sqrt(-2+x));\quad x\ne 2

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solvefor f,f(sqrt(x-2))=2x^2-x+5

solve for

f, f (x - 2) = 2 x^{2} - x + 5

f = \frac{2 x ^{2} - x + 5}{- 2 + x}; x \neq = 2

Solution steps

f (x - 2) = 2 x^{2} - x + 5

Divide both sides by

x - 2; x \neq = 2

f = \frac{2 x ^{2} - x + 5}{- 2 + x}; x \neq = 2

8 (x - 9) = - 2 (x + 41)

9 (x - 7) = 2 (3 x - 12)

50 (- 0.07) = 15 (0.55 - x)

3 (2 x - 8) = 2 (4 x + 12)

3 (x + 3) = 5 (1 - x) - 1

What is the answer to solvefor f,f(sqrt(x-2))=2x^2-x+5 ?
The answer to solvefor f,f(sqrt(x-2))=2x^2-x+5 is f=(2x^2-x+5)/(sqrt(-2+x));\quad x\ne 2