What is the answer to (3+2i)+(2+bi)=5-4i ?

The answer to (3+2i)+(2+bi)=5-4i is b=-6

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(3+2i)+(2+bi)=5-4i

(3 + 2 i) + (2 + bi) = 5 - 4 i

b = - 6

Solution steps

(3 + 2 i) + (2 + bi) = 5 - 4 i

Group the real part and the imaginary part of the complex number

(a + bi) \pm (c + d i) = (a \pm c) + (b \pm d) i

(3 + 2) + (2 + b) i = 5 - 4 i

3 + 2 = 5

5 + i (2 + b) = 5 - 4 i

Move

5

to the right side

i (2 + b) = - 4 i

Divide both sides by

i

2 + b = - 4

Move

2

to the right side

b = - 6

2 (x - 4) = 7 - 5 (2 x + 1)

4 x + 5 = 9 x - 7

x, \frac{x - 2}{4} - \frac{y - x}{2} = x - 7

2 (14 + 4 z) = - 44

\frac{( 6 - 4 ) ^{3} \cdot x}{12 \cdot 29 9 ^{2}} = 0.5 \cdot 1 0^{- 2}

What is the answer to (3+2i)+(2+bi)=5-4i ?
The answer to (3+2i)+(2+bi)=5-4i is b=-6