What is the answer to solvefor a,Z=(a-8)+(b-2)i ?

The answer to solvefor a,Z=(a-8)+(b-2)i is a=(Z+8)+i(2-b)

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solvefor a,Z=(a-8)+(b-2)i

solve for

a, Z = (a - 8) + (b - 2) i

a = (Z + 8) + i (2 - b)

Solution steps

Z = (a - 8) + (b - 2) i

Switch sides

a - 8 + (b - 2) i = Z

a - 8 + i (b - 2) = Z

Move

i (b - 2)

to the right side

a - 8 = Z - i (b - 2)

Move

8

to the right side

a = Z - i (b - 2) + 8

Simplify

a = (Z + 8) + i (2 - b)

5 x + 6 = 10

\frac{2 s - 10}{4} = 3 s + 4

4 (x - 2) - 3 = 11 x - (x - 1)

\frac{( 58.692 \cdot 65 + x \cdot 15 )}{80} = 56.15

x, 3 y - 7 x = - 9

What is the answer to solvefor a,Z=(a-8)+(b-2)i ?
The answer to solvefor a,Z=(a-8)+(b-2)i is a=(Z+8)+i(2-b)