What is the answer to solvefor z,2x+3z(x-1)^2=0 ?

The answer to solvefor z,2x+3z(x-1)^2=0 is z=-(2x)/(3(x-1)^2);\quad x\ne 1

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solvefor z,2x+3z(x-1)^2=0

solve for

z, 2 x + 3 z (x - 1)^{2} = 0

z = - \frac{2 x}{3 ( x - 1 ) ^{2}}; x \neq = 1

Solution steps

2 x + 3 z (x - 1)^{2} = 0

Move

2 x

to the right side

3 z (x - 1)^{2} = - 2 x

Divide both sides by

3 (x - 1)^{2}; x \neq = 1

z = - \frac{2 x}{3 ( x - 1 ) ^{2}}; x \neq = 1

5 x + 2 = x + 10

x, f = \frac{3}{9000} Q^{3} - \frac{1}{2} Q + 1000

3 (0) + 2 y = 5

9 = x 3

- 0.002 x + 4 = 0

What is the answer to solvefor z,2x+3z(x-1)^2=0 ?
The answer to solvefor z,2x+3z(x-1)^2=0 is z=-(2x)/(3(x-1)^2);\quad x\ne 1