What is the answer to solvefor v,v(r)=(r-r)kr^2 ?

The answer to solvefor v,v(r)=(r-r)kr^2 is v=0

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solvefor v,v(r)=(r-r)kr^2

solve for

v, v (r) = (r - r) k r^{2}

v = 0

Solution steps

v (r) = (r - r) k r^{2}

Add similar elements:

r - r = 0

v r = 0 \cdot k r^{2}

Apply rule

0 \cdot a = 0

v r = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

v = 0

2 [x + 3 (x + 1)] = 5 x

\frac{2 k}{5} + \frac{k}{2} = 18

3 \cdot (x - 2) - (x + 1) = 5

\frac{3}{4} + \frac{1}{2} = x - \frac{2}{7}

4 x - 6 [2 x - 3 (5 x - 8)] = 20

What is the answer to solvefor v,v(r)=(r-r)kr^2 ?
The answer to solvefor v,v(r)=(r-r)kr^2 is v=0