What are the solutions to the equation x^2-7x-1=0 ?

The solutions to the equation x^2-7x-1=0 are x=(7+sqrt(53))/2 ,x=(7-sqrt(53))/2

Find the zeros of x^2-7x-1=0

The zeros of x^2-7x-1=0 are x=(7+sqrt(53))/2 ,x=(7-sqrt(53))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 7 x - 1 = 0

x = \frac{7 + 53}{2}, x = \frac{7 - 53}{2}

Decimal Notation

x = 7.14005 \dots, x = - 0.14005 \dots

Solution steps

x^{2} - 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 1) = 53

x_{1, 2} = \frac{- ( - 7 ) \pm 53}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 53}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 53}{2 \cdot 1}

x = \frac{- ( - 7 ) + 53}{2 \cdot 1} : \frac{7 + 53}{2}

x = \frac{- ( - 7 ) - 53}{2 \cdot 1} : \frac{7 - 53}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 53}{2}, x = \frac{7 - 53}{2}

x^{2} - 16 x + 15

2 x^{2} + x \geq 1

(3 z - 2)^{2} = 4

(4 a)^{2}

x^{2} + 13 x - 12 = 0

What are the solutions to the equation x^2-7x-1=0 ?
The solutions to the equation x^2-7x-1=0 are x=(7+sqrt(53))/2 ,x=(7-sqrt(53))/2
Find the zeros of x^2-7x-1=0
The zeros of x^2-7x-1=0 are x=(7+sqrt(53))/2 ,x=(7-sqrt(53))/2