What is the answer to (x+2)+(x-1)=0 ?

The answer to (x+2)+(x-1)=0 is x=-1/2

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(x+2)+(x-1)=0

(x + 2) + (x - 1) = 0

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

(x + 2) + (x - 1) = 0

Remove parentheses:

(a) = a

x + 2 + x - 1 = 0

Group like terms

x + x + 2 - 1 = 0

Add similar elements:

x + x = 2 x

2 x + 2 - 1 = 0

Add/Subtract the numbers:

2 - 1 = 1

2 x + 1 = 0

Move

1

to the right side

2 x = - 1

Divide both sides by

2

x = - \frac{1}{2}

2.25 x = x^{2} - 25

lo g_{11} (600) = 1.4

\frac{2}{n} (\frac{n !}{2 ^{n + 1}})

8.5867 (2.0409 6^{3}) - 6.44 (2.04096) + 4 = x

x + 2 \leq \frac{1}{x + 2}