What is the answer to (2x+4)/4-2(x-3)=5-(7x)/2 ?

The answer to (2x+4)/4-2(x-3)=5-(7x)/2 is x=-1

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(2x+4)/4-2(x-3)=5-(7x)/2

\frac{2 x + 4}{4} - 2 (x - 3) = 5 - \frac{7 x}{2}

x = - 1

Solution steps

\frac{2 x + 4}{4} - 2 (x - 3) = 5 - \frac{7 x}{2}

Multiply by LCM

2 x + 4 - 8 (x - 3) = 20 - 14 x

Expand

2 x + 4 - 8 (x - 3) : - 6 x + 28

- 6 x + 28 = 20 - 14 x

Move

28

to the right side

- 6 x = - 14 x - 8

Move

14 x

to the left side

8 x = - 8

Divide both sides by

8

x = - 1

3 x + 11 = 8 x + 6

i, (2 m - 1) + 7 i = 9 + (3 n - 2) i

x + 2 [3 - 2 (x - 1)] = 2 [x - 3 (x - 4)] + x

x, y + 5 x - 7 = 0

27 \cdot \frac{2 ( 5 + x )}{3} - 18 x = 90

What is the answer to (2x+4)/4-2(x-3)=5-(7x)/2 ?
The answer to (2x+4)/4-2(x-3)=5-(7x)/2 is x=-1
Solve for x: (2x+4)/4-2(x-3)=5-(7x)/2
The solution is x=-1