What is the answer to i= j/i+j,i> j/2 i,i< j/(3j) ?

The answer to i= j/i+j,i> j/2 i,i< j/(3j) is j=-1/2+i 1/2

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i= j/i+j,i> j/2 i,i< j/(3j)

i = \frac{j}{i} + j, i > \frac{j}{2} i, i < \frac{j}{3 j}

j = - \frac{1}{2} + i \frac{1}{2}

Solution steps

i = \frac{j}{i} + j

Switch sides

\frac{j}{i} + j = i

Multiply both sides by

i

j + ji = - 1

Factor

j + ji : (1 + i) j

(1 + i) j = - 1

Divide both sides by

1 + i

j = - \frac{1}{2} + i \frac{1}{2}

f = 3^{5}

\frac{3 a + 1}{2} - \frac{2 a + 3}{5} = 1

\frac{4 - x}{2} = 2

\frac{5 ( x - 3 )}{2} = \frac{x \cdot 7}{3} - 1

\frac{y}{2} = 5

What is the answer to i= j/i+j,i> j/2 i,i< j/(3j) ?
The answer to i= j/i+j,i> j/2 i,i< j/(3j) is j=-1/2+i 1/2