What is the answer to T=(4^3(8 4/3)^{-n})/((4(4^{-1))^n)^2} ?

The answer to T=(4^3(8 4/3)^{-n})/((4(4^{-1))^n)^2} is T=2^{4n+2}(28/3)^{-n}

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T=(4^3(8 4/3)^{-n})/((4(4^{-1))^n)^2}

T = \frac{4 ^{3} ( 8 \frac{4}{3} ) ^{- n}}{( 4 ( 4 ^{- 1} ) ^{n} ) ^{2}}

T = 2^{4 n + 2} (\frac{28}{3})^{- n}

Solution steps

T = \frac{4 ^{3} ( 8 \frac{4}{3} ) ^{- n}}{( 4 ( 4 ^{- 1} ) ^{n} ) ^{2}}

Convert mixed numbers to improper fractions:

8 \frac{4}{3} = \frac{28}{3}

T = \frac{4 ^{3} ( \frac{28}{3} ) ^{- n}}{( 4 ( 4 ^{- 1} ) ^{n} ) ^{2}}

Simplify

\frac{4 ^{3} ( \frac{28}{3} ) ^{- n}}{( 4 ( 4 ^{- 1} ) ^{n} ) ^{2}} : 2^{4 n + 2} (\frac{28}{3})^{- n}

T = 2^{4 n + 2} (\frac{28}{3})^{- n}

\frac{x + 3}{2} = \frac{2 x}{5}

(x + 5) (x - 1) = (x + 1)^{2}

(k_{5} + 140) = 130

1.5 p = 75

D, E = 0.8809 D

What is the answer to T=(4^3(8 4/3)^{-n})/((4(4^{-1))^n)^2} ?
The answer to T=(4^3(8 4/3)^{-n})/((4(4^{-1))^n)^2} is T=2^{4n+2}(28/3)^{-n}