What is (2x^4y^2*yx^{-3})/((2x^2y^2*yx^{-1))^{-3}} ?

The solution to (2x^4y^2*yx^{-3})/((2x^2y^2*yx^{-1))^{-3}} is 16y^{12}x^4

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simplify (2x^4y^2yx^{-3})/((2x^2y^2yx^{-1))^{-3}}

simplify

\frac{2 x ^{4} y ^{2} \cdot y x ^{- 3}}{( 2 x ^{2} y ^{2} \cdot y x ^{- 1} ) ^{- 3}}

16 y^{12} x^{4}

Solution steps

\frac{2 x ^{4} y ^{2} y x ^{- 3}}{( 2 x ^{2} y ^{2} y x ^{- 1} ) ^{- 3}}

Simplify

2 x^{4} y^{2} y x^{- 3} : 2 x y^{3}

= \frac{2 x y ^{3}}{( 2 x ^{2} y ^{2} y x ^{- 1} ) ^{- 3}}

Simplify

(2 x^{2} y^{2} y x^{- 1})^{- 3} : 2^{- 3} \cdot \frac{1}{x ^{6}} \cdot \frac{1}{y ^{6}} y^{- 3} x^{3}

= \frac{2 x y ^{3}}{2 ^{- 3} \cdot \frac{1}{x ^{6}} \cdot \frac{1}{y ^{6}} y ^{- 3} x ^{3}}

\frac{2}{2 ^{- 3}} = 2^{4}

= \frac{2 ^{4} x y ^{3}}{\frac{1}{x ^{6}} \cdot \frac{1}{y ^{6}} y ^{- 3} x ^{3}}

Simplify

\frac{y ^{3}}{y ^{- 3}} : y^{6}

= \frac{2 ^{4} x y ^{6}}{\frac{1}{x ^{6}} \cdot \frac{1}{y ^{6}} x ^{3}}

Simplify

\frac{x}{x ^{3}} : \frac{1}{x ^{2}}

= \frac{2 ^{4} y ^{6}}{\frac{1}{x ^{6}} \cdot \frac{1}{y ^{6}} x ^{2}}

Simplify

\frac{2 ^{4} y ^{6}}{\frac{1}{x ^{6}} \cdot \frac{1}{y ^{6}} x ^{2}} : 16 y^{12} x^{4}

= 16 y^{12} x^{4}

x^{2} + 4 x + 29 = 0

(\frac{1}{4})^{\frac{5}{2}}

0.9 = 0.4 m

20 - x - x^{2}

x^{4} - x^{2} - 6

What is (2x^4y^2*yx^{-3})/((2x^2y^2*yx^{-1))^{-3}} ?
The solution to (2x^4y^2*yx^{-3})/((2x^2y^2*yx^{-1))^{-3}} is 16y^{12}x^4