What is the answer to ((x-2))/3+((x+3))/2 =20 ?

The answer to ((x-2))/3+((x+3))/2 =20 is x=23

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((x-2))/3+((x+3))/2 =20

\frac{( x - 2 )}{3} + \frac{( x + 3 )}{2} = 20

x = 23

Solution steps

\frac{( x - 2 )}{3} + \frac{( x + 3 )}{2} = 20

\frac{x - 2}{3} + \frac{x + 3}{2} = 20

Multiply by LCM

2 (x - 2) + 3 (x + 3) = 120

Expand

2 (x - 2) + 3 (x + 3) : 5 x + 5

5 x + 5 = 120

Move

5

to the right side

5 x = 115

Divide both sides by

5

x = 23

f (u) = ln (\frac{1 + u}{1 - u})

\frac{m + 4}{5} + 2 = \frac{m}{3}

\frac{3}{4} n + 2 = - 4

4 y - 10 = 0

x, \frac{5 x}{12} - y = 9

What is the answer to ((x-2))/3+((x+3))/2 =20 ?
The answer to ((x-2))/3+((x+3))/2 =20 is x=23
Solve for x: ((x-2))/3+((x+3))/2 =20
The solution is x=23