What is the answer to (3x+1)^2-2x=9(x+1)*(x-1)1+2(3x+1) ?

The answer to (3x+1)^2-2x=9(x+1)*(x-1)1+2(3x+1) is x=4

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(3x+1)^2-2x=9(x+1)*(x-1)1+2(3x+1)

(3 x + 1)^{2} - 2 x = 9 (x + 1) \cdot (x - 1) 1 + 2 (3 x + 1)

x = 4

Solution steps

(3 x + 1)^{2} - 2 x = 9 (x + 1) (x - 1) \cdot 1 + 2 (3 x + 1)

Multiply the numbers:

9 \cdot 1 = 9

(3 x + 1)^{2} - 2 x = 9 (x + 1) (x - 1) + 2 (3 x + 1)

Expand

(3 x + 1)^{2} - 2 x : 9 x^{2} + 4 x + 1

Expand

9 (x + 1) (x - 1) + 2 (3 x + 1) : 9 x^{2} + 6 x - 7

9 x^{2} + 4 x + 1 = 9 x^{2} + 6 x - 7

Move

1

to the right side

9 x^{2} + 4 x = 9 x^{2} + 6 x - 8

Subtract

9 x^{2} + 6 x

from both sides

9 x^{2} + 4 x - (9 x^{2} + 6 x) = 9 x^{2} + 6 x - 8 - (9 x^{2} + 6 x)

Simplify

- 2 x = - 8

Divide both sides by

- 2

x = 4

x, f (x - 1) = 2 x + 3

x, 9 x + 6 y = - 24

6 x = 60

g (- 2) = - \frac{3}{2} (2)^{- 2}

x, 3 x - 4 y + 4 = 0

What is the answer to (3x+1)^2-2x=9(x+1)*(x-1)1+2(3x+1) ?
The answer to (3x+1)^2-2x=9(x+1)*(x-1)1+2(3x+1) is x=4
Solve for x: (3x+1)^2-2x=9(x+1)*(x-1)1+2(3x+1)
The solution is x=4