What is the answer to (x+1)/4-(x-2)/3 =(x+3)/2-x-1 ?

The answer to (x+1)/4-(x-2)/3 =(x+3)/2-x-1 is x=-1

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(x+1)/4-(x-2)/3 =(x+3)/2-x-1

\frac{x + 1}{4} - \frac{x - 2}{3} = \frac{x + 3}{2} - x - 1

x = - 1

Solution steps

\frac{x + 1}{4} - \frac{x - 2}{3} = \frac{x + 3}{2} - x - 1

Multiply by LCM

3 (x + 1) - 4 (x - 2) = 6 (x + 3) - 12 x - 12

Expand

3 (x + 1) - 4 (x - 2) : - x + 11

Expand

6 (x + 3) - 12 x - 12 : - 6 x + 6

- x + 11 = - 6 x + 6

Move

11

to the right side

- x = - 6 x - 5

Move

6 x

to the left side

5 x = - 5

Divide both sides by

5

x = - 1

x, 3 x + 3 y - 6 = 0

- 2 b - (- 7) = 11

120 = 2 x - (15 - 7 x)

x, 4 x + 4 y = 80

x, 4 x + 4 y = 200

What is the answer to (x+1)/4-(x-2)/3 =(x+3)/2-x-1 ?
The answer to (x+1)/4-(x-2)/3 =(x+3)/2-x-1 is x=-1
Solve for x: (x+1)/4-(x-2)/3 =(x+3)/2-x-1
The solution is x=-1