What is factor 81(7a+3)^4-72(7a+3)^2+16 ?

The solution to factor 81(7a+3)^4-72(7a+3)^2+16 is 49(21a+11)^2(3a+1)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 81(7a+3)^4-72(7a+3)^2+16

factor

81 (7 a + 3)^{4} - 72 (7 a + 3)^{2} + 16

49 (21 a + 11)^{2} (3 a + 1)^{2}

Solution steps

81 (7 a + 3)^{4} - 72 (7 a + 3)^{2} + 16

Let

u = (7 a + 3)^{2}

= 81 u^{2} - 72 u + 16

Factor

81 u^{2} - 72 u + 16 : (9 u - 4) (9 u - 4)

= (9 u - 4) (9 u - 4)

Substitute back

u = (7 a + 3)^{2}

= (9 (7 a + 3)^{2} - 4) (9 (7 a + 3)^{2} - 4)

Factor

9 (7 a + 3)^{2} - 4 : (3 (7 a + 3) + 2) (3 (7 a + 3) - 2)

= (3 (7 a + 3) + 2) (3 (7 a + 3) - 2) (9 (7 a + 3)^{2} - 4)

Factor

9 (7 a + 3)^{2} - 4 : (3 (7 a + 3) + 2) (3 (7 a + 3) - 2)

= (3 (7 a + 3) + 2) (3 (7 a + 3) - 2) (3 (7 a + 3) + 2) (3 (7 a + 3) - 2)

Refine

= (3 (7 a + 3) + 2)^{2} (3 (7 a + 3) - 2)^{2}

(3 (7 a + 3) + 2)^{2} = (21 a + 11)^{2}

= (21 a + 11)^{2} (3 (7 a + 3) - 2)^{2}

(3 (7 a + 3) - 2)^{2} = 49 (3 a + 1)^{2}

= 49 (21 a + 11)^{2} (3 a + 1)^{2}

87 + 1263

2 x^{2} + 10 x - 31 = 7 x

\frac{1}{7} + \frac{3}{5} \geq \frac{x}{35}

- 0.75 p - 2 = 0.25 p

∣ x + 7 ∣ + 8 = 7

What is factor 81(7a+3)^4-72(7a+3)^2+16 ?
The solution to factor 81(7a+3)^4-72(7a+3)^2+16 is 49(21a+11)^2(3a+1)^2