What are the solutions to the equation p^2+5p=14 ?

The solutions to the equation p^2+5p=14 are p=2,p=-7

Find the zeros of p^2+5p=14

The zeros of p^2+5p=14 are p=2,p=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

p^{2} + 5 p = 14

p = 2, p = - 7

Solution steps

p^{2} + 5 p = 14

Move

14

to the left side

p^{2} + 5 p - 14 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

p_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 5 + 9}{2 \cdot 1}, p_{2} = \frac{- 5 - 9}{2 \cdot 1}

p = \frac{- 5 + 9}{2 \cdot 1} : 2

p = \frac{- 5 - 9}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

p = 2, p = - 7

9 d - 9 = 3 d - 1.8

3 x^{2} - 10 x + 3

\frac{( x + 1 ) ( x - 2 ) ^{2} ( x ) ^{2}}{( x + 6 ) ^{2} ( x + 3 ) ^{2}} \leq 0

5 x = 6 x - 7

- x - 3 < 0

What are the solutions to the equation p^2+5p=14 ?
The solutions to the equation p^2+5p=14 are p=2,p=-7
Find the zeros of p^2+5p=14
The zeros of p^2+5p=14 are p=2,p=-7