What are the solutions to the equation x^2-8x-4=0 ?

The solutions to the equation x^2-8x-4=0 are x=2(2+sqrt(5)),x=2(2-sqrt(5))

Find the zeros of x^2-8x-4=0

The zeros of x^2-8x-4=0 are x=2(2+sqrt(5)),x=2(2-sqrt(5))

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x^{2} - 8 x - 4 = 0

x = 2 (2 + 5), x = 2 (2 - 5)

Decimal Notation

x = 8.47213 \dots, x = - 0.47213 \dots

Solution steps

x^{2} - 8 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 4) = 45

x_{1, 2} = \frac{- ( - 8 ) \pm 4 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 5}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 4 5}{2 \cdot 1}

x = \frac{- ( - 8 ) + 4 5}{2 \cdot 1} : 2 (2 + 5)

x = \frac{- ( - 8 ) - 4 5}{2 \cdot 1} : 2 (2 - 5)

The solutions to the quadratic equation are:

x = 2 (2 + 5), x = 2 (2 - 5)

(x) (1 \cdot 1 0^{- 4}) = (1 \cdot 1 0^{- 5}) (25)

7.5 3

3 x - 1 < 14

4 m - 5 < m + 2

(4 x - 7)^{2} = - 16

What are the solutions to the equation x^2-8x-4=0 ?
The solutions to the equation x^2-8x-4=0 are x=2(2+sqrt(5)),x=2(2-sqrt(5))
Find the zeros of x^2-8x-4=0
The zeros of x^2-8x-4=0 are x=2(2+sqrt(5)),x=2(2-sqrt(5))