What is the answer to x-{2+[x-(3x-1)]}=2-x ?

The answer to x-{2+[x-(3x-1)]}=2-x is x= 5/4

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x-{2+[x-(3x-1)]}=2-x

x - {2 + [x - (3 x - 1)]} = 2 - x

x = \frac{5}{4}

Decimal

x = 1.25

Solution steps

x - {2 + [x - (3 x - 1)]} = 2 - x

x - (2 + x - (3 x - 1)) = 2 - x

Expand

x - (2 + x - (3 x - 1)) : 3 x - 3

3 x - 3 = 2 - x

Move

3

to the right side

3 x = - x + 5

Move

x

to the left side

4 x = 5

Divide both sides by

4

x = \frac{5}{4}

a (4 x - 10) = 24 x + 5 b

x, \frac{x}{2} - \frac{y}{4} = 1

x, 7 x + 2 y = 31

- \frac{346250}{245542} = \frac{484160}{491085}

5 (2 x - 10) = \frac{x}{2} + 4

What is the answer to x-{2+[x-(3x-1)]}=2-x ?
The answer to x-{2+[x-(3x-1)]}=2-x is x= 5/4
Solve for x: x-{2+[x-(3x-1)]}=2-x
The solution is x= 5/4