What are the solutions to the equation 16000=-0.1x^2+80x ?

The solutions to the equation 16000=-0.1x^2+80x are x=400

Find the zeros of 16000=-0.1x^2+80x

The zeros of 16000=-0.1x^2+80x are x=400

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16000 = - 0.1 x^{2} + 80 x

x = 400

Solution steps

16000 = - 0.1 x^{2} + 80 x

Multiply both sides by

10

160000 = - x^{2} + 800 x

Switch sides

- x^{2} + 800 x = 160000

Move

160000

to the left side

- x^{2} + 800 x - 160000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 800 \pm 80 0 ^{2} - 4 ( - 1 ) ( - 160000 )}{2 ( - 1 )}

80 0^{2} - 4 (- 1) (- 160000) = 0

x_{1, 2} = \frac{- 800 \pm 0}{2 ( - 1 )}

x = \frac{- 800}{2 ( - 1 )}

\frac{- 800}{2 ( - 1 )} = 400

x = 400

The solution to the quadratic equation is:

x = 400

a^{2} + b^{2}

2 5^{\frac{3}{2}}

r^{2} - 12 r + 36

\frac{4}{7} + \frac{5}{6} - \frac{4}{3}

(180) (0.305)

What are the solutions to the equation 16000=-0.1x^2+80x ?
The solutions to the equation 16000=-0.1x^2+80x are x=400
Find the zeros of 16000=-0.1x^2+80x
The zeros of 16000=-0.1x^2+80x are x=400