What is the answer to (x-1)/2+x/3-(2-x)/6 = 7/6 ?

The answer to (x-1)/2+x/3-(2-x)/6 = 7/6 is x=2

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(x-1)/2+x/3-(2-x)/6 = 7/6

\frac{x - 1}{2} + \frac{x}{3} - \frac{2 - x}{6} = \frac{7}{6}

x = 2

Solution steps

\frac{x - 1}{2} + \frac{x}{3} - \frac{2 - x}{6} = \frac{7}{6}

Multiply by LCM

3 (x - 1) + 2 x - (2 - x) = 7

Expand

3 (x - 1) + 2 x - (2 - x) : 6 x - 5

6 x - 5 = 7

Move

5

to the right side

6 x = 12

Divide both sides by

6

x = 2

5.3 = \frac{x}{4.6}

6 (x - 3) - 9 (x - 5) = x - 1

\frac{1}{12} c + \frac{1}{6} = - \frac{1}{3}

x, x + y - 2 z = 0

3 (4 x - 1) - 2 (5 x - 3) = 11 - 2 x + 16

What is the answer to (x-1)/2+x/3-(2-x)/6 = 7/6 ?
The answer to (x-1)/2+x/3-(2-x)/6 = 7/6 is x=2
Solve for x: (x-1)/2+x/3-(2-x)/6 = 7/6
The solution is x=2