What is the answer to solvefor x,y=2f(x/2-1)+3 ?

The answer to solvefor x,y=2f(x/2-1)+3 is x=(y-3)/f+2;\quad f\ne 0

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solvefor x,y=2f(x/2-1)+3

solve for

x, y = 2 f (\frac{x}{2} - 1) + 3

x = \frac{y - 3}{f} + 2; f \neq = 0

Solution steps

y = 2 f (\frac{x}{2} - 1) + 3

Switch sides

2 f (\frac{x}{2} - 1) + 3 = y

Move

3

to the right side

2 f (\frac{x}{2} - 1) = y - 3

Divide both sides by

2 f; f \neq = 0

\frac{x}{2} - 1 = \frac{y - 3}{2 f}; f \neq = 0

Move

1

to the right side

\frac{x}{2} = \frac{y - 3}{2 f} + 1; f \neq = 0

Multiply both sides by

2

x = \frac{y - 3}{f} + 2; f \neq = 0

x, 2 p = 40 - 0.01 x

j, j (t) = (3 t^{2} + 2 t) (t^{4} - 3 t + 1)

0.001 x = 2.005 \cdot 10 \cdot 200.5

\frac{a}{3} - \frac{9}{2} = 2 a + 1

x, x + y = 72

What is the answer to solvefor x,y=2f(x/2-1)+3 ?
The answer to solvefor x,y=2f(x/2-1)+3 is x=(y-3)/f+2;\quad f\ne 0