What is the answer to -6(y+1)+8y=2(y-3) ?

The answer to -6(y+1)+8y=2(y-3) is True for all y

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-6(y+1)+8y=2(y-3)

- 6 (y + 1) + 8 y = 2 (y - 3)

True for all y

Solution steps

- 6 (y + 1) + 8 y = 2 (y - 3)

Expand

- 6 (y + 1) + 8 y : 2 y - 6

Expand

2 (y - 3) : 2 y - 6

2 y - 6 = 2 y - 6

Move

6

to the right side

2 y = 2 y

Move

2 y

to the left side

0 = 0

Both sides are equal

True for all y

4 (x + 1) = 3 x + 4

- 1 s < - 6

(- a^{6} b)^{2} + 9 a^{12} b^{2}

x^{2} + 12 x - 45 = 0

- 7 \leq \frac{x + 2}{4}

What is the answer to -6(y+1)+8y=2(y-3) ?
The answer to -6(y+1)+8y=2(y-3) is True for all y
Solve for y: -6(y+1)+8y=2(y-3)
The solution is True for all y